42x^2+37x-14=0

Solution for 42x^2+37x-14=0 equation:

42x^2+37x-14=0

a = 42; b = 37; c = -14;
Δ = b2-4ac
Δ = 372-4·42·(-14)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-61}{2*42}=\frac{-98}{84}
=-1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+61}{2*42}=\frac{24}{84}
=2/7
$